u=(\frac{1}{\sqrt2}) \[ u=(\frac{1}{\sqrt2})\]
u=\left(\frac{1}{\sqrt2}\right) \[ u=\left(\frac{1}{\sqrt2}\right)\]
u=\bigg(\frac{1}{\sqrt2}\bigg) \[ u=\bigg(\frac{1}{\sqrt2}\bigg)\]
u=\Big(\frac{1}{\sqrt2}\Big) \[ u=\Big(\frac{1}{\sqrt2}\Big)\]
u=\Bigg(\frac{1}{\sqrt2}\Bigg) \[ u=\Bigg(\frac{1}{\sqrt2}\Bigg)\]
KTUG 한국 텍 사용자 그룹
u=(\frac{1}{\sqrt2}) \[ u=(\frac{1}{\sqrt2})\]
u=\left(\frac{1}{\sqrt2}\right) \[ u=\left(\frac{1}{\sqrt2}\right)\]
u=\bigg(\frac{1}{\sqrt2}\bigg) \[ u=\bigg(\frac{1}{\sqrt2}\bigg)\]
u=\Big(\frac{1}{\sqrt2}\Big) \[ u=\Big(\frac{1}{\sqrt2}\Big)\]
u=\Bigg(\frac{1}{\sqrt2}\Bigg) \[ u=\Bigg(\frac{1}{\sqrt2}\Bigg)\]